X(2x-4)=2x^2-5(x-1)

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Solution for X(2x-4)=2x^2-5(x-1) equation: 



X(2X-4)=2X^2-5(X-1)

We move all terms to the left:

X(2X-4)-(2X^2-5(X-1))=0

We multiply parentheses

2X^2-4X-(2X^2-5(X-1))=0



We calculate terms in parentheses: -(2X^2-5(X-1)), so:

2X^2-5(X-1)

We multiply parentheses

2X^2-5X+5

Back to the equation:

-(2X^2-5X+5)



We get rid of parentheses

2X^2-2X^2-4X+5X-5=0

We add all the numbers together, and all the variables

X-5=0

We move all terms containing X to the left, all other terms to the right

X=5

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